2002 Chemijos Vbe Atsakymai ((install))

Sample answer: The substance could be identified as glucose (C6H12O6) based on its positive reaction with Benedict's reagent and its sweet taste.

Bet ar iš tiesų jis buvo toks paprastas, ir kur dabar rasti teisingus ? Pasinerkime į istoriją. 2002 chemijos vbe atsakymai

m(BaCl2)=m(tirpalo)×w=200 g×0,10=20 gm open paren cap B a cap C l sub 2 close paren equals m open paren t i r p a l o close paren cross w equals 200 space g cross 0 comma 10 equals 20 space g Sample answer: The substance could be identified as